If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12x^2+12x+5=7
We move all terms to the left:
12x^2+12x+5-(7)=0
We add all the numbers together, and all the variables
12x^2+12x-2=0
a = 12; b = 12; c = -2;
Δ = b2-4ac
Δ = 122-4·12·(-2)
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{15}}{2*12}=\frac{-12-4\sqrt{15}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{15}}{2*12}=\frac{-12+4\sqrt{15}}{24} $
| 2(8g-20)=(g-1)+4 | | –34+x=4 | | 17x-4=5x | | 1+√3x+8=18 | | 2025=27(5x-15) | | 7.2+x=3.4 | | F(x)=8x3+4x-2 | | 12-8d-2d=-38 | | -4r-5(r+10)=-68 | | 4(q-4)=7q+5 | | 3d-2(d+9)=-25 | | (2c+3c+7=3+8) | | 10b-4(b-3)=30 | | 2x-10+x-70+90=180 | | .m=8-2 | | 10b-(4b-3)=30 | | 2x+10+x-70=180 | | 2x+10-x-70+90=180 | | 90=6d+4d | | 180/3/7=x | | 2x+10+x-70+90=180 | | 2x+5(3-2x)=18 | | 14=8-h | | 8=8(12+p) | | -12u-4=11u+4 | | 32=-8(w-3) | | 18=-6(4+t)-12 | | 2=6–p | | -3=-6+w/6 | | -30=5d-5 | | 44-10x=76 | | -32=5c+3c |